Respuesta :

The temperature of the air mass would be 5°C after it rises.

Air temperature drops 1°C for every 100 m it rises:

1/100 = x/500

Cross multiply:
500*1 = 100*x
500=100x

Divide both sides by 100:
500/100 = 100x/100
5 = x

The temperature will drop 5°; 10-5 = 5°C for the new temperature.

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