we have that
Choose the equation of a line in standard form that satisfies the given conditions. perpendicular to 4x + y = 8 through (4, 3)
4x + y = 8-----> y=-4x+8-----> the slope m is -4
we know that
if two lines are perpendicular
then
m1*m2=-1
m1=-4
so
m2=1/4
with m=1/4 and point (4,3)
find the equation of the line
y=mx+b
3=(1/4)*4+b-----> 3=1+b-----> b=2
y=(1/4)*x+2------> (1/4)*x-y=-2-----> multiply by 4----> x-4y=-8
the answer is the option
A. x − 4y = −8
