Tim, with mass 79.8 kg, climbs a gymnasium rope a distance of 5.3 m. the acceleration of gravity is 9.8 m/s 2 . how much potential energy does tim gain? answer in units of j.
The gravitational potential energy gained by Tim is given by the following equation: [tex]\Delta U = mg \Delta h[/tex] where m is Tim's mass g is the gravitational acceleration [tex]\Delta h[/tex] is the vertical distance covered by Tim
If we substitute the data given by the problem into the equation, we find how much potential energy Tim has gained: [tex]\Delta U=(79.8 kg)(9.81 m/s^2)(5.3 m)=4149 J[/tex]
