Let the equation of the given line be y=mx+a. This line has slope m and the parallel line will have the same slope. Then the equation of the parallel line to the line y=mx+a will be y=mx+b. Since line passes through the point (–2, 2), the coordinates of this point suit the equation: 2=m·(-2)+b, 2=-2m+b, b=2+2m and the equation is y=mx+2m+2. You should only to paste correct m from the given equation.
