The correct answer is option C
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Explanation of the answer:
It is given that ⇒ a₁ = -6
So, we need to find which of the options will give us -6 by substituting with n=1
⇒ substitute with n = 1 in the equation of option A
∴[tex] a_{1} = -4*( \frac{1}{6} )^{n-1} = -4*( \frac{1}{6} )^{1-1}=-4*( \frac{1}{6} )^0 = -4[/tex]
⇒ substitute with n = 1 in the equation of option B
[tex] a_{1} = \frac{1}{4} *(-6)^{n-1} = \frac{1}{4} *(-6)^{1-1} = \frac{1}{4} *(-6)^0 = \frac{1}{4} [/tex]
⇒ substitute with n = 1 in the equation of option C
∴[tex] a_{1} = -6*( \frac{1}{4} )^{n-1} = -6*( \frac{1}{4} )^{1-1}=-6*( \frac{1}{4} )^0 = -6[/tex]
⇒ substitute with n = 1 in the equation of option D
[tex] a_{1} = \frac{1}{6} *(-4)^{n-1} = \frac{1}{6} *(-4)^{1-1} = \frac{1}{6} *(-4)^0 = \frac{1}{6} [/tex]
