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07-09-2018
Physics

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Calculate the force of attraction between a ca2+ and an o2- ion whose centers are separated by a distance of 1.25 nm g

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aristocles aristocles

17-09-2018

excess charge on each ion is equivalent to the charge of two electrons

now we have

[tex]q = 2e = 3.2 * 10^{-19}C[/tex]

now the electrostatic force between them is given by

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

[tex]F = \frac{9*10^9 * 3.2* 10^{-19}* 3.2 * 10^{-19}}{1.25 * 10^{-9}^2}[/tex]

so from above the force between them is

[tex]F = 5.89 * 10^{-10} N[/tex]

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