KingChoco7
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What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) ?



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trytodepress

The base length is 3 - (-1) = 4 units   (vertical side DE).

The height is 3 - (-2) = 5 units   (horizontal segment from F to the intersection with vertical segment DE).


The area of the triangle is ([tex]\frac{1}{2}[/tex])*5*4 = 10 square units.


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