The rectangle below has an area of 14x^4 + 6x^2 square meters. The width of the rectangle (in meters) is equal to the greatest common monomial factor of 14x^4 and 6x^2. What is the length and width of the rectangle?

Respuesta :

Answer:

Width: [tex]2x^{2}[/tex]

Lenght: [tex](7x^{2}+3)[/tex]

Step-by-step explanation:

1. The prime factorization of the monomial is:

[tex]14x^{4}=2*7*x*x*x*x\\6x^{2}=2*3*x*x[/tex]

2. The product of the common factors is:

[tex]2*x*x=2x^{2}[/tex]

3. The greatest common monomial factor is: [tex]2x^{2}[/tex]

4.  The formula for calculate the area of a rectangle is:

[tex]A=L*W[/tex]

Where L is the length and W is the width

5. Therefore, if the greatest common monomial factor monomial of the area of [tex]14x^{4}+6x^{2}[/tex] is  [tex]2x^{2}[/tex] and the area is the product of the lenght and the width, you have that the lenght is:

[tex]2x^{2}(7x^{2}+3)[/tex]

Length:

[tex](7x^{2}+3)[/tex]