Respuesta :
Answer:
a) 0.0387; b) 0.8435; c) 0.1564
Step-by-step explanation:
Using a graphing calculator, for part a, we use Bpd, binomial probability distribution.
In this problem, n = 5300 since it is the number of trials. The probability of success, or in this case the probability that the items are scanned incorrectly, is 0.0069. For part a, x = 30; running this on the calculator, we get 0.0387.
For part b, we will use Bcd, the cumulative binomial distribution. Our number of trials is still 5300, and our p (probability of success) is still 0.0069. In this question, x is still 30. The Bcd function will give us the probability that less than or equal to 30 are scanned incorrectly; this means once we find this value, we subtract from 1.
The calculator gives us 0.1565; this means our answer for part b is 1-0.1565 = 0.8435.
For part c, we already have the probability of less than 30 items being scanned from part b; this is 0.1565.
The probability of less than or equal to 16 items being scanned incorrectly is 0.000106. To find the probability between these values we subtract:
0.1565-0.000106 = 0.156394 ≈ 0.1564