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One component of a magnetic field has a magnitude of 0.0404 T and points along the x axis while the other component has a magnitude of 0.0739 T and points along the y axis A particle carrying a charge of 2.80 10 5 C is moving along the z axis at a speed of 4.46 103 m s a Find the magnitude of the net magnetic force that acts on the particle b Determine the angle that the net force makes with respect to the x axis

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Answer:

as we find the resultant of the magnetic field we get in the xy plane. Just perpendicular to this plane i.e. along z-axis the charge is moving. Hence the force acting on the charge will also be in the xy plane.  

Net field = ./(0.078^2 +0.070^2) = 0.105 T  

Angle with x axis is arc tan 0.070/0.072 = 44.2 deg  

So the force acting on the moving charge is got by Bqv  

0.105*5.5*10^-5 * 6*10^3 = 0.03465 N  

So the angle inclined by this force with x axis will be 90+44.2 = 134.2

Explanation:

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