contestada

Indicate the coordination number for the central metal atom in each of the following coordination compounds:
(a) [Pt(H2O)2Br2]
(b) [Pt(NH3)(py)(Cl)(Br)] (py = pyridine, C5H5N)
(c) [Zn(NH3)2Cl2]
(d) [Zn(NH3)(py)(Cl)(Br)]
(e) [Ni(H2O)4Cl2]
(f) [Fe(en)2(CN)2]+ (en = ethylenediamine, C2H8N2)

Respuesta :

InesWalston

Answer: A. 4, since all 4 ligands (2 H2O&2Br) are monodentate hence 4x1=4

B. 4, (4x1=4)

C. 4(4x1=4)

D. 4(4x1=4)

E. 6(6x1=6)

F. 6(2(2)+2(1)=4+2=6) en is bidentate ligand

Explanation:

Coordination number is equal to number of ligands surrounded the metal atom.

Coordination number= No of ligands X denticity

Denticity is nothing but nature of ligands like mono, bi dentate, or tetrads rate etc.

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