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A 384 m long train is moving on a straight track with a speed of 77.3 km/h. The engineer applies the brakes at a crossing, and later the back of the last car passing the crossing with a speed of 19.5 km/h. Assuming constant acceleration, determine how long the train blocked the crossway. Disregard the width of the crossing. Convert the time into three different units: s, min, and hr.

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Answer:

The time the train blocked the crossway is

0.007934h=0.476 min=28.6 s

Explanation:

The average speed is given by

V= (Vi+Vf)/2

and

V= dx/dt

Where

Vi= initial speed

Vf= final speed

dx= change of position=0.384 km

dt=time the train blocked the crossway

dt=2dx/(Vi+Vf)

dt=2*0.384 km/(77.3 +19.5) km/h

dt=0.007934h

dt=0.007934h*(60min/1h)=0.476 min

dt=0.476 min*(60s/1min)=28.6 s

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