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Three boxes rest side-by-side on a smooth, horizontal floor. Their masses are 5.0 kg, 3.0 kg, and 2.0 kg, with the 3.0-kg mass in the center. A force of 50 N pushes on the 5.0-kg box, which pushes against the other two boxes. What magnitude force does the 5.0-kg box exert on the 3.0-kg box?

Respuesta :

Answer:25 N

Explanation:

Given

mass of 5 , 3 & 2 kg blocks lie on floor

Force on 50 N pushes the 5 kg box

[tex]Let N_1[/tex] be the reaction on 2 kg box therefore

[tex]N_1=2\times a[/tex]

where a is the acceleration of the system

[tex]N_2=[/tex]reaction on 3 kg block by 5 kg block

[tex]N_2-N_1=3a[/tex]

[tex]N_2=5a[/tex]

Now for 5 kg block

[tex]F-N_2=5a[/tex]

F=10a

[tex]a=\frac{F}{10}=5 m/s^2[/tex]

Force exerted by 5 kg block on 3 kg block is

[tex]N_2=5\times 5=25 N[/tex]

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