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Astronauts aboard the U.S.S. Burger decide to fire the rocket thrusters for 3.0 seconds to make a course correction. While the thrusters are on, the ship moves a total distance of 10,500 kilometers and increases its speed by 340 meters / sec. What is the U.S.S. Burger’s Δ V, (where V stands for speed) in meters / second?

Respuesta :

Answer:

340 m/s

Solution:

As per the question;

Time, t = 3.0 s

Total distance moved by the ship, d = 10,500 km

The increase in speed, v = 340 m/s

Now,

To calculate the U.S.S Burger's change in speed, [tex]\Delta V[/tex]:

The final velocity is given by:

[tex]v_{f} = 340 + v_{i}[/tex]                      (1)

where

[tex]v_{f} = final\ velocity[/tex]

[tex]v_{i} = initial\ velocity[/tex]

Also, the change in velocity is given by:

[tex]\Delta v = v_{f} - v_{i}[/tex]                    (2)

Now, from eqn (1) and (2):

[tex]\Delta = 340 + v_{i} - v_{i} = 340\ m/s[/tex]

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