A buoy starts at a height of 0 in relation to sea level and then goes up. Its maximum displacement in either direction is 6 feet, and the time it takes to go from its highest point to its lowest point is 4 seconds. Which of the following equations can be used to model h, the height in feet of the buoy in relation to sea level as a function of time, t, in seconds?

Respuesta :

Answer:

h= 6 sine (pi/4 times t)

Answer:

[tex]y=6sin(\frac{\pi}{4}t)[/tex]

Step-by-step explanation:

This problem is about an harmonic movement. The definition, that relates the given variables in this kind of movement is:

[tex]y=Asin(\omega t)[/tex]

Where [tex]y[/tex] is the vertical displacement, [tex]t[/tex] is the time and [tex]\omega = \frac{2 \pi}{T}[/tex]

So, we just have find the angular frequency and then replace all given values:

[tex]\omega = \frac{2 \pi}{T}=\frac{2 \pi}{8}=\frac{\pi}{4}[/tex]

In this case, the period [tex]T[/tex] is 8 seconds, because according to the problem, half period is 4 second, from the highest point to the lowest, which is half of the complete period.

Now, replacing values:

[tex]y=6sin(\frac{\pi}{4}t)[/tex]

This expression, where [tex]y[/tex] is the height or vertical displacement, gives the height at any point.