Answer:
The mean and the standard error of the distribution of the sample mean are 200 and 2.
Step-by-step explanation:
Consider the provided information.
Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18
Sample size = n = 81
Mean = μ=200
Standard deviation = σ = 18
The mean of the distribution of the sample mean is same as the mean of the population. [tex]\mu_x=\mu=200[/tex]
The standard error can be calculated as: [tex]S.E.=\dfrac{\sigma}{\sqrt{n}}[/tex]
Substitute the respective values in the above formula.
[tex]S.E.=\dfrac{18}{\sqrt{81}}=\dfrac{18}{9}=2[/tex]
Hence, the mean and the standard error of the distribution of the sample mean are 200 and 2.
