Respuesta :

Answer:

Step-by-step explanation:

3*2x=6x, 3*5=10

So, 6x+10+4x = 5x+15

Add 6 and 4 which leaves you with 10x+10 = 5x+15

subtract 10 from 15 and that leaves you with 5 divided by 10x

x=2

Same for second equation

2*8x=16x and 2*3= 6

So 16x-6=16x+28

Add 6 to both sides so you get 34.

Now that 6 is gone you want x on one side so subtract 16x an it leaves you with 0. so X=34

zumar
  • [tex]3(2x-5)+4x=5x+15\\6x-15+4x=5x+15\\6x-15+4x-5x-15=0\\6x+4x-5x-15-15=0\\5x-30=0\\5x=30\\x=30/5\\x=6[/tex]
  • [tex]2(8x-3)=4(4x+7)\\16x-6=16x-28\\16x-16x=6-28\\0\neq -22[/tex] its soluion does not exist

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