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A rocket burns fuel at a rate of 180 kg/s and exhausts the gas at a relative speed of 1 km/s. Find the thrust of the rocket. Answer in units of MN.

Respuesta :

boffeemadrid

Answer:

0.18 MN

Explanation:

m = Mass

t = Time taken

u = Initial velocity = 0

v = Final velocity = 1 km/s

[tex]\frac{m}{t}[/tex] = Mass flow rate = 180 kg/s

Force is given by

[tex]F=\frac{m(v-u)}{t}\\\Rightarrow F=\frac{m}{t}(1000-0)\\\Rightarrow F=180\times 1000\\\Rightarrow F=0.18\times 10^{6}\ N\\\Rightarrow F=0.18\ MN[/tex]

The thrust on the rocket is 0.18 MN