Answer:
L_max= 0
Explanation:
The formula for magnitude of maximum orbital angular momentum is given by
[tex]L_{max}= \sqrt{l(l+1)\bar{h}}[/tex]
l= orbital quantum number
l= n-1
n= shell number or principal quantum number
for n=1 , l=0
therefore, [tex]L_{max}= \sqrt{0(0+1)\bar{h}}[/tex]
L_max= 0
