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A girl throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s, and it bounces back with this same speed. The ball is in contact with the wall 0.05 s. What is the average force exerted on the wall by the ball?

Respuesta :

Answer:

F = 352 N

Explanation:

we know that:

F*t = ΔP

so:

F*t = M[tex]V_f[/tex]-M[tex]V_i[/tex]

where F is the force excerted by the wall, t is the time, M the mass of the ball, [tex]V_f[/tex] the final velocity of the ball and [tex]V_i[/tex] the initial velocity.

Replacing values, we get:

F(0.05s) = (0.8 kg)(11m/s)-(0.8 kg)(-11m/s)

solving for F:

F = 352 N

 

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