07-10-2014
Mathematics

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Solve for h: S=2B+Ph

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07-10-2014

[tex]S=2B+Ph\ \ \ \ \ \ \ \ \ \ \ \ |Subtract\ 2B\\\\S-2B=Ph\ \ \ \ \ \ \ \ \ \ \ \ |:P\\\\h=\frac{S-2B}{P}[/tex]

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