Respuesta :
Answer:
The segment is 6 units long.
Step-by-step explanation:
The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.
If two points at the ends of a straight line PQ are P([tex]x_{1},y_{1}[/tex]) and Q([tex]x_{2},y_{2}[/tex]), then the length of the segment PQ will be given by the formula
[tex]\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}[/tex]
Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be
[tex]\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6[/tex] units. (Answer)
The length of the segment is 6 units.
It is given that,
- Points (–2, 4) and (–2, –2) are vertices of a heptagon.
To find the length of the segment formed by these endpoints.
Explanation:
The distance formula is used to find the length of the segment formed by two endpoints.
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(-2-(-2))^2+(-2-4)^2}[/tex]
[tex]d=\sqrt{(0)^2+(-6)^2}[/tex]
On further simplification, we get
[tex]d=\sqrt{36}[/tex]
[tex]d=6[/tex]
Thus, the length of the segment is 6 units.
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