The points (–2, 4) and (–2, –2) are vertices of a heptagon. Explain how to find the length of the segment formed by these endpoints. How long is the segment?

Respuesta :

Answer:

The segment is 6 units long.

Step-by-step explanation:

The points (–2, 4) and (–2, –2) are vertices of a heptagon. We have to explain how to find the length of the segment formed by these endpoints.

If two points at the ends of a straight line PQ are P([tex]x_{1},y_{1}[/tex]) and Q([tex]x_{2},y_{2}[/tex]), then the length of the segment PQ will be given by the formula  

[tex]\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}[/tex]

Now, in our case the two points are (-2,4) and (-2,-2) and the length of the segment will be  

[tex]\sqrt{(- 2 - (- 2))^{2} + (4 - (- 2))^{2}} = 6[/tex] units. (Answer)

The length of the segment is 6 units.

It is given that,

  • Points (–2, 4) and (–2, –2) are vertices of a heptagon.

To find the length of the segment formed by these endpoints.

Explanation:

The distance formula is used to find the length of the segment formed by two endpoints.

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]d=\sqrt{(-2-(-2))^2+(-2-4)^2}[/tex]

[tex]d=\sqrt{(0)^2+(-6)^2}[/tex]

On further simplification, we get

[tex]d=\sqrt{36}[/tex]

[tex]d=6[/tex]

Thus, the length of the segment is 6 units.

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