Answer:
0.128 rad/s², 7.66 rad/s
Explanation:
length, l = 66.4 cm
initial angular speed, ωo = 0 rad/s
Let ω be the final angular speed.
Let α be the angular acceleration.
number of revolution, n = 36.6
time, t = 1 min = 60 second
Angle turned, θ = 2πn = 2 x 3.14 x 36.6 = 229.85 rad
Use second equation of motion for angular motion
[tex]\theta =\omega _{0}t+\frac{1}{2}\alpha t^{2}[/tex]
229.85 = 0 + 0.5 x α x 60 x 60
α = 0.128 rad/s²
Use first equation of motion
ω = ωo + αt
ω = 0 + 0.128 x 60
ω = 7.66 rad/s
