Answer:
1.15 rad/s²
Explanation:
given,
angular speed of turntable = 45 rpm
=[tex]45\times \dfrac{2\pi}{60}[/tex]
=[tex]4.71\ rad/s[/tex]
time, t = 4.10 s
initial angular speed = 0 rad/s
angular acceleration.
[tex]\alpha = \dfrac{\omega_f-\omega_0}{t}[/tex]
[tex]\alpha = \dfrac{4.71-0}{4.10}[/tex]
[tex]\alpha = 1.15\ rad/s^2[/tex]
Hence, the angular acceleration of the turntable is 1.15 rad/s²
