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As a research assistant, you are asked to prepare a 3.00 liter solution of magnesium sulfate at 45.0 micromoles per liter. How many moles of magnesium sulfate are required to make this solution?

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Eduard22sly

Answer:

Explanation:

From the question given, we obtained the following:

Molarity = 45.0 micromoles per liter = 45x10^-6mol/L

Volume = 3L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 45x10^-6 x 3

Mole = 1.35x10^-4 moles

Therefore, 1.35x10^-4 moles of magnesium sulfate is needed to make the solution.

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