They were going at a velocity 4.07m/s
Explanation:
Distance s =5 m
initial velocity u= 0.8 m/s
Acceleration a =1.6m/s2
We have to calculate the velocity with which they were going afterwards i.e final velocity.
Use the equation of motion
[tex]v^2=u^2+2as\\=0.8^2+2\times 1.6\times 5\\=16.64\\v=4.07 m/s[/tex]
They were going with a velocity 4.07 m/s afterwards.
