Answer:
Vector of the average velocity = 3.33 km\hr towards south.
Explanation:
Given:
Distance covered by the student = [tex]7[/tex] miles = [tex]7\times 1.6 =11.2[/tex] km
Total displacement = [tex]10[/tex] km in [tex]South[/tex]
Total time taken = [tex]20[/tex] mins = [tex]\frac{20}{60} = 0.33[/tex] hr
Note:
Odometer reading is the distance covered while straight-line distance is the displacement which is the shortest route.
Distance is scaler where as displacement is a vector quantity.
Scaler has only magnitude while vector has magnitude and direction.
We have to find the average velocity.
Average velocity = Ratio of total displacement and total time.
⇒ Average velocity ([tex]v[/tex]) = [tex]\frac{displacement \ (x)}{time\ (t)}[/tex]
⇒ Plugging the values.
⇒ ([tex]v[/tex]) = [tex]\frac{10}{0.33}[/tex]
⇒ ([tex]v[/tex]) = [tex]3.33[/tex] km\hr
So the vector of the average velocity = 3.33 km\hr towards south.
