Answer:
Answer is attached. locate First image to see answer.
Explanation:
Let us label the carbons from left to right as a, b, and c. The first two carbons have three objects about them and the third has two. None of the carbons has any spare lone pairs. (Later on, it will seem quite straightforward to view these as sp2, sp2, and sp hybridization, respectively--but we are not that far along yet!)
Anyway, here are the various bond angles. Except for a missing lone pair at the right of the terminal N, teh structure as drawn is the Lewis structure.
