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Methanol (CH3OH) is produced commercially by the catalyzed reaction of carbon monoxide and hydrogen:

CO(g)+2H2(g)⇌CH3OH(g).

An equilibrium mixture in a 1.50 L vessel is found to contain 0.0679 mol CH3OH, 0.160 mol CO, and 0.302 mol H2 at 500 K.

Required:
Calculate Kc at this temperature.

Respuesta :

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Answer: Kc= 4.653

Explanation:

From The equation of reaction

CO(g)+2H2(g)⇌CH3OH(g)

From the question

[CH3OH] =0.0679 moles

[CO]= 0.160moles

[H2]= 0.302

Kc = [CH3OH]/[CO] [H2]^2

Kc=[0.069]/[0.16]×[0.302]^2

Kc= 4.653

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