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The following data summarizes results from 952 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedistrian was intoxicated or the diriver was intoxicatedo

Pedestrian intoxicated
yes (81) (51)
no (225) (552)

Respuesta :

MrRoyal

Answer:

0.3927

Step-by-step explanation:

Given

Pedestrian intoxicated

Yes (81) (51) ---- (132)

No (225) (552) --- (777)

Total: (306) (603) --- (909)

Let P(P) = the probability that the pedistrian was intoxicated

Let P(D) = T probability that the diriver was intoxicated

To calculate P(D or P)?

P(D or P) is given as P(D) + P(P) - P(P and D)

P(P) = 306/909

P(D) = 132/909

P(P and D) = 81/909

P(P or D) = 306/909 + 132/909 - 81/909

P(P or D) = 357/909

P(P or D) = 0.3927

eve24great2001

Answer:

0.139

Step-by-step explanation:

Number of pedestrians that were intoxicated 81

Number of pedestrians that were not intoxicated 225

Number of drivers that were intoxicated 51

Number of drivers that were not intoxicated 552

Total number of deaths 952

Probability of pedestrians intoxicated or driver intoxicated is

81/952 + 51/952 = 132/952 = 0.139

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