Answer:
Horizontal component = 16.8 m/s
Vertical component = 46.0 m/s
Explanation:
If we denote the initial velocity by v and the angle above the horizontal by θ,
the horizontal component of this initial velocity is given by
[tex]v_x = v\cos \theta[/tex]
[tex]v_x = (49.0\text{ m/s})\cos\,(70.0^\circ) = 16.8\text{ m/s}[/tex]
The vertical component is given by
[tex]v_y = v\sin\theta[/tex]
[tex]v_x = (49.0\text{ m/s})\sin\,(70.0^\circ) = 46.0\text{ m/s}[/tex]
