Answer:
E(x)=138
Step-by-step explanation:
let x be the number of times a '3' shows up from a toss.
-Assuming, Susan tosses a fair the die, with 6 sides, each side has an equal probability of showing up:
[tex]P(s)=P(1)=P(2)....=P(5)=P(6)=\frac{1}{6}[/tex]
Given that the coin is tossed 828 times, the expected value of x is calculated as:
[tex]E(x)=np\\\\=828\times \frac{1}{6}\\\\=138[/tex]
Hence, the expected value of 3 in 828 tosses is 138
*Answer not in options provided.
