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If 3 mole of gas at 0 °C has a pressure of 6 atm what is the volume of the gas?
R= 0.0821 L*atm/mol*K.

Respuesta :

Answer:

The volume of the gas is 11, 2 L.

Explanation:

We use the ideal gas formula. We first convert the unit of temperature in degrees Celsius to Kelvin. We use the ideal gas constant R = 0.082 l atm / K mol. We solve v (volume) :

273K =0°C

PV=nRT ---> V= (nRT)/P

V= ( 3 mol x  0.082 l atm / K mol x 273 K) / 6 atm

V= 11, 193 L

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