Answer:
The mass of bodily fluid lost per hour is 0.369 kg
Explanation:
Mass of runner [tex]m = 61.8[/tex] kg
Energy produced by the body [tex]E = 279[/tex] J
Here 11.3% of energy is delivered to the muscle tissue, that implies 88.7% of this energy used to evaporate the sweat as heat.
Heat energy used in one hour is
[tex]Q = 279 \times 0.887 \times 3600[/tex]
[tex]Q = 8.9 \times 10^{5}[/tex] [tex]\frac{J}{hr}[/tex]
From the formula of latent heat,
[tex]Q = L_{V} m[/tex]
Where [tex]L_{V} = 2.41 \times 10^{6}[/tex] [tex]\frac{J}{kg}[/tex] ( Latent heat of vaporization for water )
[tex]m = \frac{Q}{L_{V} }[/tex]
[tex]m = \frac{8.9 \times 10^{5} }{2.41 \times 10^{6} }[/tex]
[tex]m = 0.369[/tex] kg
Therefore, the mass of bodily fluid lost per hour is 0.369 kg
The mass of bodily fluid lost per hour is 0.37 kg
The given parameters;
The excess energy is removed from the body by evaporation of sweat, is calculated as follows;
[tex]Q = (1 -0.113) \times 279 \times \frac{3600 \ s}{1 \ h} \\\\Q = 8.909 \times 10^5 \ J/h[/tex]
The mass of bodily fluid lost per hour is calculated as follows;
[tex]Q = L_v m[/tex]
where;
[tex]L_v \ is \ latent \ heat \ of\ vaporization \ of \ water = 2.41 \times 10^6 \ J/kg[/tex]
[tex]m = \frac{Q}{Lv} \\\\m = \frac{8.909 \times 10^5}{2.41 \times 10^6} \\\\m = 0.37 \ kg[/tex]
Thus, the mass of bodily fluid lost per hour is 0.37 kg.
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