Answer:
A.[tex]1900 kg/m^3[/tex]
Explanation:
We are given that
[tex]m=8.6 kg[/tex]
Density,[tex]\rho_s=3400 kg/m^3[/tex]
Tension,T=38 N
We have to find the density of liquid.
[tex]T=mg-\rho_l Vg[/tex]
[tex]g=9.8 m/s^2[/tex]
Volume,V=[tex]\frac{m}{\rho_s}[/tex]
[tex]38=8.6\times 9.8-\rho_l\times \frac{8.6}{3400}\times 9.8[/tex]
[tex]\rho_l\times \frac{8.6}{3400}\times 9.8=8.6\times 9.8-38[/tex]
[tex]\rho_l=\frac{(8.6\times 9.8-38)\times 3400}{8.6\times 9.8}[/tex]
[tex]\rho_l=1867kg/m^3\approx 1900 kg/m^3[/tex]
Option A is true.