Answer:
In order to react with 45 g of water 1.25 moles of CaC₂ are required.
Explanation:
Given data:
Moles of CaC₂ needed = ?
Mass of water = 45.0 g
Solution:
Chemical equation:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45 g/ 18 g/mol
Number of moles = 2.5 mol
Now we will compare the moles of water and CaC₂ from balance chemical equation:
H₂O : CaC₂
2 : 1
2.5 : 1/2×2.5 =1.25 mol
In order to react with 45 g of water 1.25 moles of CaC₂ are required.
The number of mole of CaC₂ needed to completely react with 45 g of H₂O is 1.25 mole
We'll begin by calculating the number of mole in 45 g of H₂O.
Mass of H₂O = 45 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mole = mass / molar mass
Mole of H₂O = 45 / 18
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
From the balanced equation above,
2 moles of H₂O reacted with 1 mole of CaC₂.
Therefore,
2.5 moles of H₂O will react with = 2.5 / 2 = 1.25 mole of CaC₂.
Thus, 1.25 mole of CaC₂ is needed for the reaction.
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