block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequency ( ω ω ) of oscillation? x ( t ) = 1.5 cos ( 20 t ) x(t)=1.5cos⁡(20t)

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Muscardinus Muscardinus · Answer 1 · 2020-04-08T05:04:14+02:00

Answer:

Angular frequency is 20 rad/s.

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

[tex]x(t)=1.5\cos(20\ t)[/tex].....(1)

The general equation of oscillating particle is given by :

[tex]x(t)=A\cos(\omega t)[/tex].......(2)

Compare equation (1) and (2) we get :

[tex]\omega=20\ rad/s[/tex]

So, the angular frequency of the oscillation is 20 rad/s.

andromache andromache · Answer 2 · 2022-04-12T15:11:55+02:00

The angular frequency ( ω ω ) of oscillation should be considered as the 20 rad/s.

Since

A block should be attached to an oscillating spring.

The function below shows its position (cm) vs. time (s) should be provided by

x(t) = 15cos(20t) ....(1)

here, general equation of oscillating particle should be

x(t) = Acos(wt) ....2

So if we compare these two equations so it should be 20 rad/s

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