A technical machinist is asked to build a cubical steel tank that will hold 195 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest 0.001 m.

Respuesta :

Answer:

The smallest possible inside length of the tank is [tex]0.579[/tex] m.

Explanation:

As we know that

[tex]1 m^3 = 1000 L[/tex]

Thus, volume of [tex]195[/tex] liter tank is also equal to [tex]0.195[/tex] cubic meter

The volume of a cube is equal to [tex]x^3[/tex], where, x is the length of the side of the cube

With the give condition,

[tex]x^ 3 = 0.195[/tex]

Solving the above equation, we get -

[tex]x = (0.195)^{\frac{1}{3})}\\x = 0.579[/tex]

The smallest possible inside length of the tank is [tex]0.579[/tex] m.