Respuesta :

Answer:

26 and 27

Step-by-step explanation:

The first integer = x

Therefore the second integer = x + 1

according to the statement we obtain the equation

(x) + (x + 1) <55

x + x + 1 <55

2 * x + 1 <55

We subtract 1 from both sides, we get:

2x <54

divide both sides by 2 we get:

x <27

Therefore the first integer is 26, since it has to be better than 27.

the second integer = x + 1

= 26 + 1

= 27

If we add 26 + 27 = 53, which is less than 55 and the condition is met

To prove:

The pair of integers with the greatest sum are 26 and 27.

Let us consider the first integer to be x

Thus, the second integer = x + 1

According to the given statement we obtain the equation:

[tex](x) + (x + 1) <55\\\\x + (x + 1) <55\\\\(2 * x) + 1 <55[/tex]

On subtracting 1 from both sides we will get :

[tex]2x <54[/tex]

Further on dividing both sides by 2 we get:

[tex]x <27[/tex]

Therefore, the first integer is 26, since it has to be better than 27.

The second integer: [tex]x + 1 = 26 + 1 = 27[/tex]

If we add 26 + 27 = 53, which is less than 55 and the condition is proved.

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