Respuesta :
Answer:
26 and 27
Step-by-step explanation:
The first integer = x
Therefore the second integer = x + 1
according to the statement we obtain the equation
(x) + (x + 1) <55
x + x + 1 <55
2 * x + 1 <55
We subtract 1 from both sides, we get:
2x <54
divide both sides by 2 we get:
x <27
Therefore the first integer is 26, since it has to be better than 27.
the second integer = x + 1
= 26 + 1
= 27
If we add 26 + 27 = 53, which is less than 55 and the condition is met
To prove:
The pair of integers with the greatest sum are 26 and 27.
Let us consider the first integer to be x
Thus, the second integer = x + 1
According to the given statement we obtain the equation:
[tex](x) + (x + 1) <55\\\\x + (x + 1) <55\\\\(2 * x) + 1 <55[/tex]
On subtracting 1 from both sides we will get :
[tex]2x <54[/tex]
Further on dividing both sides by 2 we get:
[tex]x <27[/tex]
Therefore, the first integer is 26, since it has to be better than 27.
The second integer: [tex]x + 1 = 26 + 1 = 27[/tex]
If we add 26 + 27 = 53, which is less than 55 and the condition is proved.
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