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During your winter vacation, you enter a "dogsled" race across a frictionless frozen lake, in which the sleds are pulled by students instead of dogs. To get started, you pull the sled (mass m=50 kg) with a force of F=100 N at θ = 30o above the horizontal. The sled moves S = 30.0 m, starting from rest. Assume that there is no friction. (1) What is the final kinetic energy of your sled? (select the closest values)

Respuesta :

Answer:

Explanation:

mass of sled = 50 kg

Force applied F = 100 N , angle θ = 30 degree.

Component of force in horizontal direction

Fcos30

= 100 x .866

= 86.6 N

Work done in the displacement = 30 m

= force in horizontal direction x displacement

= 86.6  x 30

= 2598 J

This work done by applied force will be converted into kinetic energy

So kinetic energy of sled = 2598 J .

The final kinetic energy of the sled is 2598 J

Calculation of work done:

Given information:

The mass of sled m = 50 kg

Force applied on the sled is F = 100 N, at an angle of θ = 30°

To calculate the work done we need to find the horizontal component of the force F.

Horizontal component of force:

Fₓ = Fcos30

Fₓ = 100 × 0.866

Fₓ = 86.6 N

Work done for the displacement d = 30 m

W = force in horizontal direction × displacement

W = Fₓ × d

W = 86.6  x 30

W = 2598 J

According to the work-energy theorem:

This work done by applied force will be converted into kinetic energy

So kinetic energy of sled KE = 2598 J

Learn more about work-energy theorem:

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