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A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During a 0.10 s time interval, the magnitude of the field increases uniformly from 250 to 350 mT. (a) Determine the emf induced in the loop (in V). (Enter the magnitude.) V (b) If the magnetic field is directed out of the page, what is the direction of the current induced in the loop

Respuesta :

Answer:

Magnitude of induced emf is 0.00635 V

Explanation:

Radius of circular loop r = 45 mm = 0.045 m

Area of circular loop [tex]A=\pi r^2[/tex]

[tex]A=3.14\times 0.045^2=0.00635m^2[/tex]

Magnetic field is increases from 250 mT to 350 mT

Therefore change in magnetic field [tex]dB=250-350=100mT[/tex]

Emf induced is given by

[tex]e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}[/tex]

[tex]e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V[/tex]

Magnitude of induced emf is equal to 0.00635 V

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