Answer : The temperature [tex]Cl_2[/tex] gas is, 153 K
Explanation :
Using ideal gas equation:
[tex]PV=nRT[/tex]
where,
P = Pressure of [tex]Cl_2[/tex] gas = 900 torr = 1.18 atm (1 atm = 760 torr)
V = Volume of [tex]Cl_2[/tex] gas = 0.750 L
n = number of moles [tex]Cl_2[/tex] = 0.0705 mole
R = Gas constant = [tex]0.0821L.atm/mol.K[/tex]
T = Temperature of [tex]Cl_2[/tex] gas = ?
Putting values in above equation, we get:
[tex]1.18atm\times 0.750L=0.0705mole\times (0.0821L.atm/mol.K)\times T[/tex]
[tex]T=152.9K\approx 153K[/tex]
Therefore, the temperature [tex]Cl_2[/tex] gas is, 153 K
