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4. If an experimental value for a given observation was 415 nm while the theoretical value

was 435.8 nm, what is the percent error of the observation?

Respuesta :

tutorAnne

Answer: % error of observation is 4.77%

Explanation:

Given:

Observation value = 415nm

theoretical value= 435.8nm

Percent error of observation = theoretical value- observation value/ theoretical value x 100 %

= 435.8-415/435.8= 0.04772 x 100 = 4.77%

therefore % error of observation is 4.77%

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