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What is the pH of a 500mL solution of 0.25M HCI?

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SvetkaChem

Answer:

0.60

Explanation:

pH = - log[H+]

[HCl] = [H+] = 0.25 M, because HCl is strong acid, so it dissociates completely.

PH = -log[0.25] = 0.60

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Explanation:

[HCL] = 0.5 M

HCL(aq) -------------> H+(aq) + Cl- (aq)

[H+] = [HCl]

[H+] = 0.25M

pH = -log[H+]

pH = -log( 0.25 )

pH = 0.6

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