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A 20kg beam 4.0m long is pivoted at a wall and supported by a cable.what is the force at the wall and the tension in the cable

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tochjosh

Answer:

98.1 N

Explanation:

We assume that the weight of the beam acts at its center.

Mass m = 20 kg

Weight = mass x acceleration due to gravity 9.81 m/s^2

Weight = 20 x 9.81 = 196.2 N

Lenght of beam = 4.0 m

Taking moment about the wall

Moment is force x perpendicular distance

196.2 x 2 = T x 4

392.4 = 4T

T = 392.4/4 = 98.1 N.

See force diagram below.

Ver imagen tochjosh

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