Respuesta :

Answer:

D. [tex] \frac{4 \sqrt{33} }{33} [/tex]

Step-by-step explanation:

[tex] \tan \alpha = \frac{4}{ \sqrt{33} } \\ = \frac{4}{ \sqrt{33} } \times \frac{ \sqrt{33} }{ \sqrt{33} } \\ \\ = \frac{4 \sqrt{33} }{ {( \sqrt{33)} }^{2} } \\ \\ \tan \alpha = \frac{4 \sqrt{33} }{33} [/tex]

The answer I think is d