Answer:
10 ways
Step-by-step explanation:
The number of ways in which five basketball players could be placed in three positions is:
5[tex]C_{3}[/tex] = [tex]\frac{5!}{(5-3)!3!}[/tex]
= [tex]\frac{5!}{3!2!}[/tex]
= [tex]\frac{5*4*3*2!}{3*2*2!}[/tex]
= 5 × 2
= 10
The basketball players can be arranged in 10 ways.
Answer: 15 ways
the guy who answered before me is wrong the way you measure probability is multiplying the outcomes 3x5=15 not 10
Pls mark brainliest
