deeky09
contestada

IMPORTANT. LOTS OF POINTS. SOLVE NOW. Rays OM , ON , and OP coincide at time t=0. At the same instant in time, OM and OP begin to rotate in the plane about point O, but in opposite directions. Ray ON remains fixed. Ray OM rotates at a constant rate of 3° per second with respect to ON , while OP rotates at a constant rate of 6° per second. What is the smallest positive value of t, in seconds, in which rays OM and OP will coincide again? When t=30 min, how many more revolutions has ray OP completed than ray OM ?

Respuesta :

I believe if Socratic is right the answer is -x+4y=8

Answer:

t=40 seg OP does 15 more revolutions than OM

Step-by-step explanation:

i didn't do this, just answering it just in case someone doesnt look at the comments