Write the equation for the area of a triangle with a height that is 5 more than twice its base using one variable. Please help mee this is my last question

Respuesta :

Answer:

[tex]A=b(b+\frac{5}{2} )[/tex]

Step-by-step explanation:

hey there!!!

we know already that the area of a triangle is given as

[tex]A=\frac{1}{2}b *h[/tex]

where b= base

and h= heigth

Given that the height is 5 times more than twice it base

let h= 2b+5

Now we substitute h=2b+5 in the area of the triangle

[tex]A=\frac{1}{2}b * (2b+5)[/tex]

[tex]A= \frac{2b^2}{2} +\frac{5b}{2}[/tex]

[tex]A= b^2+\frac{5b}{2}\\\\A=b(b+\frac{5}{2} )[/tex]