What is the value of f(5) if f(3)=10 and the rate of change over the interval 3≤x≤5 is 15?(1 point

f(5)=40

f(5)=20

f(5)=5

f(5)=10

Respuesta :

The average rate of change of [tex]f(x)[/tex] over 3 ≤ x ≤ 5 is

[tex]\dfrac{f(5)-f(3)}{5-3}=15[/tex]

Solve for [tex]f(5)[/tex]:

[tex]\dfrac{f(5)-10}2=15[/tex]

[tex]f(5)-10=30[/tex]

[tex]\boxed{f(5)=40}[/tex]